## Editorial for Rock-Paper-Scissors

Remember to use this editorial only when stuck, and not to copy-paste code from it. Please be respectful to the problem author and editorialist.
Submitting an official solution before solving the problem yourself is a bannable offence.

Editorialist: PHPeasant

The only observation to make is that a game with a distinct winner must have three players matching. This cuts the branching logic into four distinct cases (one for each possible winner) each with three possible sub-cases.

An example solution in C++14 is given below:

#include <bits/stdc++.h>
using namespace std;

int main(){
ios_base::sync_with_stdio(false);
cin.tie(NULL);
string a,b,c,d;
cin >> a >> b >> c >> d;
string winner = "?";
if(a == b && a == d){
// S can win
if(c == "rock"){
if(b == "scissors")
winner = "S";
} else if(c == "paper"){
if(b == "rock")
winner = "S";
} else {
if(b == "paper")
winner = "S";
}
} else if(a == c && a == d){
// D can win
if(b == "rock"){
if(a == "scissors")
winner = "D";
} else if(b == "paper"){
if(a == "rock")
winner = "D";
} else {
if(a == "paper")
winner = "D";
}
} else if (b == c && b == d){
// A can win
if(a == "rock"){
if(b == "scissors")
winner = "A";
} else if(a == "paper"){
if(b == "rock")
winner = "A";
} else {
if(b == "paper")
winner = "A";
}
} else if (a == b && a == c){
// T can win
if(d == "rock"){
if(b == "scissors")
winner = "T";
} else if(d == "paper"){
if(b == "rock")
winner = "T";
} else {
if(b == "paper")
winner = "T";
}
}
cout << winner;
}


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