Editorial for Murder for a jar of red rum
Submitting an official solution before solving the problem yourself is a bannable offence.
Ah, palindromes! This question required that you take in a string and denote whether it is palindrome, ignoring case, punctuation and whitespace.
This problem can be solved in \(O(n)\) by reading in the string, transforming it character by character to lower-case (e.g. using C++
transform(str.begin(), str.end(), str.begin(), ::tolower)) and then simply checking the front and the back of the string to see if the two results are the same while skipping anything that isn't an alphabetical character. If you make it through the whole string, then its a palindrome and you can print
True otherwise, print
Most teams took a few attempts at this, mostly because almost everyone missed that punctuation doesn't matter for the purposes of this question.